Trắc nghiệm Hàm số lượng giác Toán Lớp 11

A. \(T=2\pi\)

B. \(T=\pi\)

C. \(T=k2\pi\)

D. \(T=k\pi\)

A. \(T=\pi\)

B. \(T=2\pi\)

C. \(T=\frac{\pi}{3}\)

D. \(T=\frac{\pi}{2}\)

A. \(y=\sin 2 x\)

B. \(y=2\sin x\)

C. \(y=\sin x\)

D. \(y=\sin x+2\)

A. \(y=\cos \left(x+\frac{\pi}{3}\right) . \)

B. \(y=|\sin x| \)

C. \(y=1-\sin x\)

D. \(y=\sin x+\cos x.\)

A. \(\begin{array}{ll} y=\sin \left(x+\frac{\pi}{4}\right)+\tan \left(x+\frac{\pi}{4}\right) . \end{array}\)

B. \(y=\tan x-\frac{1}{\sin x} .\)

C. \(y=\sin ^{4} x-\cos ^{4} x . \)

D. \( y=\cos x .\)

A. \(y=x^{2} \cos x.\)

B. \(y=\sin 2 x.\)

C. \(y=\sin ^{2} x.\)

D. \(y=\cos 2x .\)

A. \(y=\sin \left(\frac{\pi}{2}-x\right) . \)

B. \(y=\tan x . \)

C. \(y=\sin x \text {. } \)

D. \(y=\sin \left(x+\frac{\pi}{6}\right) \text {. }\)

A. \(y=-2 \sin x \)

B. \(y=2 \sin 2 x.\)

C. \(y=\sin x-\cos x.\)

D. \(y=-2 \cos x.\)

A. \(y=1+\sin x\)

B. \(y=x \cdot \tan x\)

C. \(y=\sin ^{5} x\)

D. \(y=\cos x \cdot \sin ^{2} x\)

A. \(y=\tan x\)

B. \(y=\cot x\)

C. \(y=\sin x\)

D. \(y=\cos x\)

A. \(y=\sin x\)

B. \(y=\tan x\)

C. \(y=\cot x\)

D. \(y=\cos x\)

A. \(y=\cos x\)

B. \(y=\sin 2x\)

C. \(y=\cot 4x\)

D. \(y=\tan 6x\)

A. \(x \neq k \pi \text { với } k \in \mathbb{Z} \text {. }\)

B. \(x \neq k 2 \pi \text { với } k \in \mathbb{Z} \text {. }\)

C. \(x \neq \frac{\pi}{2}+ k 2 \pi \text { với } k \in \mathbb{Z} \text {. }\)

D. \(x\in \mathbb{R} \)

A. \(D=\mathbb{R} \backslash\{2\} .\)

B. \(D=\mathbb{R}\)

C. \(D=(-\infty;-2)\)

D. \(D=(2;+\infty)\)

A. \(D=\mathbb{R} \backslash\left\{-\frac{\pi}{2}+k \pi, k \in \mathbb{Z}\right\} \text {. }\)

B. \(D=\mathbb{R} \)

C. \(D=\mathbb{R} \backslash\left\{-\frac{\pi}{2}+k 2 \pi, k \in \mathbb{Z}\right\} \text {. }\)

D. \(D=\mathbb{R} \backslash\left\{\frac{3\pi}{2}+k 2 \pi, k \in \mathbb{Z}\right\} \text {. }\)

A. \(D=\mathbb{R} \)

B. \(D=\mathbb{R} \backslash\left\{\frac{\pi}{2}+k 2 \pi \mid k \in \mathbb{Z}\right\} \text {. }\)

C. \(D=\mathbb{R} \backslash\left\{-\frac{\pi}{3}+k 2 \pi \mid k \in \mathbb{Z}\right\} \text {. }\)

D. \(D=\mathbb{R} \backslash\left\{-\frac{\pi}{2}+k 2 \pi \mid k \in \mathbb{Z}\right\} \text {. }\)

A. \(D=\mathbb{R} \backslash\{k \pi \mid k \in \mathbb{Z}\}\)

B. \(D=\mathbb{R} \)

C. \(D=\mathbb{R} \backslash\{\frac{\pi}{2}+k \pi \mid k \in \mathbb{Z}\}\)

D. \(D=\mathbb{R} \backslash\{\frac{\pi}{3}+k \pi \mid k \in \mathbb{Z}\}\)

A. \(\mathbb{R} \backslash\left\{\frac{\pi}{4}+k \frac{\pi}{2}, \frac{\pi}{2}+k \pi \mid k \in \mathbb{Z}\right\}\)

B. \(\mathbb{R}\)

C. \(\mathbb{R} \backslash\left\{\frac{\pi}{3}+k \frac{\pi}{2}, \frac{\pi}{2}+k \pi \mid k \in \mathbb{Z}\right\}\)

D. \(\mathbb{R} \backslash\left\{\frac{\pi}{2}+k \pi \mid k \in \mathbb{Z}\right\}\)

A. \(\begin{array}{ll} D=R \backslash\{(2 k+1) \pi, k \in \mathbb{Z}\} \end{array}\)

B. \(D=R \backslash\left\{\frac{k \pi}{2}, k \in \mathbb{Z}\right\}\)

C. \(D=R \backslash\left\{(2 k+1) \frac{\pi}{2}, k \in \mathbb{Z}\right\} \)

D. \( D=R \backslash\{k \pi, k \in \mathbb{Z}\}\)

A. \(D=\mathbb{R} \backslash\{\frac{\pi}{3}+k 2 \pi \mid k \in \mathbb{Z}\} \text {. }\)

B. \(D=\mathbb{R} \backslash\{k \pi \mid k \in \mathbb{Z}\} \text {. }\)

C. \(D=\mathbb{R} \backslash\{k 2 \pi \mid k \in \mathbb{Z}\} \text {. }\)

D. \(D=\mathbb{R} \backslash\{\frac{\pi}{2}+k 2 \pi \mid k \in \mathbb{Z}\} \text {. }\)

A. \(x=k \pi, k \in \mathbb{Z} \text {. }\)

B. \( \mathbb{R} \backslash\{k2 \pi, k \in \mathbb{Z}\} \text {. }\)

C. \( \mathbb{R}\)

D. \( \mathbb{R} \backslash\{k \pi, k \in \mathbb{Z}\} \text {. }\)

A. \(D= \mathbb{R} \backslash\left\{\frac{\pi}{2}+k 2 \pi \mid k \in \mathbb{Z}\right\} \text {. }\)

B. \(D= \mathbb{R} \backslash\left\{\frac{\pi}{3}+k 2 \pi \mid k \in \mathbb{Z}\right\} \text {. }\)

C. \(D= \mathbb{R} \backslash\left\{\pm\frac{\pi}{2}+k 2 \pi \mid k \in \mathbb{Z}\right\} \text {. }\)

D. \(D= \mathbb{R} \backslash\left\{\frac{3\pi}{2}+k 2 \pi \mid k \in \mathbb{Z}\right\} \text {. }\)

A. \(D=\mathbb{R} \backslash\left\{\frac{\pi}{2}+k \pi, k \in \mathbb{Z}\right\}\)

B. \( x=\frac{\pi}{2}+k 2 \pi, k \in \mathbb{Z} \text {. }\)

C. \( x=\pm\frac{\pi}{2}+k 2 \pi, k \in \mathbb{Z} \text {. }\)

D. \( x=\frac{\pi}{3}+k 2 \pi, k \in \mathbb{Z} \text {. }\)

A. \(D=\mathbb{R} \backslash\{\frac{\pi}{3}+k \pi, k \in \mathbb{Z}\} \text {. }\)

B. \(D=\mathbb{R} \backslash\{\frac{\pi}{2}+k \pi, k \in \mathbb{Z}\} \text {. }\)

C. \(D=\mathbb{R} \backslash\{k \pi, k \in \mathbb{Z}\} \text {. }\)

D. \(D=\mathbb{R} \)

A. \(D=\mathbb{R} \backslash\left\{\frac{\pi}{3}+\frac{k \pi}{2}, k \in \mathbb{Z}\right\} \text {. }\)

B. \(D=\mathbb{R}\)

C. \(D=\mathbb{R} \backslash\left\{\pm\frac{\pi}{3}+\frac{k \pi}{2}, k \in \mathbb{Z}\right\} \text {. }\)

D. \(D=\mathbb{R} \backslash\left\{\frac{\pi}{6}+\frac{k \pi}{2}, k \in \mathbb{Z}\right\} \text {. }\)

A. \( D=\mathbb{R} \backslash\left\{\frac{\pi}{2}+k \pi, k \in \mathbb{Z}\right\} \text {. }\)

B. \( D=\mathbb{R} \backslash\left\{\frac{3\pi}{2}+k \pi, k \in \mathbb{Z}\right\} \text {. }\)

C. \( D=\mathbb{R} \backslash\left\{k \pi, k \in \mathbb{Z}\right\} \text {. }\)

D. \(D=\mathbb{R} \backslash\left\{-\frac{\pi}{2}+k \pi, k \in \mathbb{Z}\right\} \text {. }\)

A. \(D=\mathbb{R} \backslash\left\{\frac{\pi}{3}+k 2 \pi, k \in \mathbb{Z}\right\} \text {. }\)

B. \(D=\mathbb{R} \backslash\left\{\frac{3\pi}{2}+k 2 \pi, k \in \mathbb{Z}\right\} \text {. }\)

C. \(D=\mathbb{R} \backslash\left\{\frac{\pi}{4}+k 2 \pi, k \in \mathbb{Z}\right\} \text {. }\)

D. \(D=\mathbb{R} \backslash\left\{\frac{\pi}{2}+k 2 \pi, k \in \mathbb{Z}\right\} \text {. }\)

A. \( D=\left\{\frac{5\pi}{2}+k 2 \pi \mid k \in \mathbb{Z}\right\}\)

B. \( D=\left\{\frac{\pi}{2}+k 2 \pi \mid k \in \mathbb{Z}\right\}\)

C. \( D=\left\{\frac{3\pi}{2}+k 2 \pi \mid k \in \mathbb{Z}\right\}\)

D. \( D=\left\{\frac{\pi}{3}+k 2 \pi \mid k \in \mathbb{Z}\right\}\)

A. \(D=\mathbb{R} \backslash\{\pi+k \pi, k \in \mathbb{Z}\} \text {. }\)

B. \(D=\mathbb{R} \backslash\{\pi+k 2 \pi, k \in \mathbb{Z}\} \text {. }\)

C. \(D=\mathbb{R} \backslash\{\frac{3\pi}{2}+k 2 \pi, k \in \mathbb{Z}\} \text {. }\)

D. \(D=\mathbb{R} \backslash\{\frac{\pi}{2}+k 2 \pi, k \in \mathbb{Z}\} \text {. }\)

A. \(D=\mathbb{R} \backslash\left\{k \frac{\pi}{2}, k \in \mathbb{Z}\right\} \text {. }\)

B. \(D=\mathbb{R} \backslash\left\{k \frac{3\pi}{2}, k \in \mathbb{Z}\right\} \text {. }\)

C. \(D=\mathbb{R} \backslash\left\{\frac{\pi}{2}+k \frac{\pi}{3}, k \in \mathbb{Z}\right\} \text {. }\)

D. \(D=\mathbb{R} \backslash\left\{\frac{\pi}{2}+k \frac{\pi}{2}, k \in \mathbb{Z}\right\} \text {. }\)

A. \(x=\frac{3\pi}{2}+k \pi\)

B. \(x=\frac{\pi}{3}+k \pi\)

C. \(x=\frac{\pi}{2}+k \pi\)

D. \(x=k \pi\)

A. \(x=2k\pi\)

B. \(x=k\pi\)

C. \(x=k\frac {3\pi}{2}\)

D. \(x=k\frac {\pi}{2}\)

A. 1

B. 0

C. -1

D. -2

A. 2

B. 1

C. 3

D. 4

A. \(x=-\frac{\pi}{4}+k \pi\)

B. \(x=\frac{\pi}{4}+k \pi\)

C. \(x=-\frac{\pi}{2}+k \pi\)

D. \(x=-\frac{3\pi}{4}+k \pi\)

A. \( x=\frac{3\pi}{4}+k \pi\)

B. \( x=\frac{\pi}{4}+k \pi\)

C. \( x=\frac{\pi}{2}+k \pi\)

D. \( x=\frac{\pi}{3}+k \pi\)

A. 1

B. -1

C. 3

D. -3

A. 3

B. 4

C. 5

D. 2

A. Hàm số f(x) là hàm số lẻ. 

B. Hàm số f(x) là hàm số chẵn. 

C. Hàm số f(x) là hàm số không lẻ không chẵn. 

D. Hàm số f(x) là hàm số vừa chẵn vừa lẻ. 

A. Hàm số f(x) là hàm số chẵn

B. Hàm số f(x) là hàm số vừa chẵn vừa lẻ. 

C. Hàm số f(x) là hàm số không chẵn không lẻ. 

D. Hàm số f(x) là hàm số lẻ. 

A. Hàm số f(x) là hàm số chẵn.

B. Hàm số f(x) là hàm số lẻ.

C. Hàm số f(x) là hàm số không chẵn không lẻ.

D. Hàm số f(x) là hàm số vừa chẵn vừa lẻ.

A. \(T=\pi\)

B. \(T=2\pi\)

C. \(T=3\pi\)

D.  Hàm số đã cho không tuần hoàn.

A. \(T=\frac{ \pi}{2} \text {. }\)

B. \(T=\frac{5 \pi}{2} \text {. }\)

C. \(T=\frac{ \pi}{4} \text {. }\)

D. Không có chu kì.

A. \(T=\pi \)

B. \(T=2\pi \)

C. \(T=\frac{3\pi}{2} \)

D. \(T=\frac{\pi}{2} \)

A. \(D=\mathbb{R} \backslash\left\{ \frac{\pi}{2}+k 2 \pi,-\frac{\pi}{14}+\frac{k 2 \pi}{7}\right\} \text {. }\)

B. \(D=\mathbb{R} \backslash\left\{\frac{\pi}{10}+\frac{k \pi}{5} ; \frac{\pi}{2}+k 2 \pi,-\frac{\pi}{14}+\frac{k 2 \pi}{7}\right\} \text {. }\)

C. \(D=\mathbb{R} \backslash\left\{\frac{3\pi}{4}+\frac{k \pi}{5} ; \frac{\pi}{2}+k 2 \pi,-\frac{\pi}{14}+\frac{k 2 \pi}{7}\right\} \text {. }\)

D. \(D=\mathbb{R} \backslash\left\{\frac{\pi}{3}+\frac{k \pi}{5} ; \frac{\pi}{2}+k 2 \pi,-\frac{\pi}{14}+\frac{k 2 \pi}{7}\right\} \text {. }\)

A. \(D=\mathbb{R} \backslash\left\{\frac{\pi}{2}+k 2 \pi,-\frac{\pi}{18}+\frac{k \pi}{3} ; k \in \mathbb{Z}\right\}\)

B. \(D=\mathbb{R} \backslash\left\{-\frac{\pi}{2}+k 2 \pi,-\frac{\pi}{18}+\frac{k \pi}{3} ; k \in \mathbb{Z}\right\}\)

C. \(D=\mathbb{R} \backslash\left\{\pm\frac{\pi}{2}+k 2 \pi,-\frac{\pi}{18}+\frac{k \pi}{3} ; k \in \mathbb{Z}\right\}\)

D. \(D=\mathbb{R} \backslash\left\{\frac{3\pi}{2}+k 2 \pi,-\frac{\pi}{18}+\frac{k \pi}{3} ; k \in \mathbb{Z}\right\}\)

A. \(D=\mathbb{R} \backslash\left\{\frac{ \pi}{3}+k \frac{\pi}{3}, k \in \mathbb{Z}\right\} \text {. }\)

B. \(D=\mathbb{R} \backslash\left\{\frac{2 \pi}{3}+k \frac{\pi}{3}, k \in \mathbb{Z}\right\} \text {. }\)

C. \(D=\mathbb{R} \backslash\left\{\frac{2 \pi}{9}+k \frac{\pi}{3}, k \in \mathbb{Z}\right\} \text {. }\)

D. \(D=\mathbb{R} \backslash\left\{\frac{ \pi}{9}+k \frac{\pi}{3}, k \in \mathbb{Z}\right\} \text {. }\)

A. \( D=\mathbb{R} \backslash\left\{\frac{2 \pi}{3}+k \pi, k \in \mathbb{Z}\right\}\)

B. \( D=\mathbb{R}\)

C. \( D=\mathbb{R} \backslash\left\{-\frac{ \pi}{3}+k \pi, k \in \mathbb{Z}\right\}\)

D. \( D=\mathbb{R} \backslash\left\{\frac{\pi}{3}+k \pi, k \in \mathbb{Z}\right\}\)

A. \(x=-\frac{\pi}{4}-\frac{k3 \pi}{2}(k \in \mathbb{Z})\)

B. \(x=-\frac{3\pi}{4}-\frac{k \pi}{2}(k \in \mathbb{Z})\)

C. \(x=-\frac{\pi}{3}-\frac{k \pi}{2}(k \in \mathbb{Z})\)

D. \(x=-\frac{\pi}{4}-\frac{k \pi}{2}(k \in \mathbb{Z})\)

A. \(\left[\begin{array}{l} x=-\frac{\pi}{4}+\frac{k \pi}{2} \\ x=-\frac{5 \pi}{12}+k \pi \end{array}(k \in \mathbb{Z}) .\right.\)

B. \(\left[\begin{array}{l} x=-\frac{\pi}{24}-\frac{k \pi}{2} \\ x=-\frac{5 \pi}{12}+k 2\pi \end{array}(k \in \mathbb{Z}) .\right.\)

C. \(\left[\begin{array}{l} x=-\frac{\pi}{24}-\frac{k \pi}{2} \\ x=-\frac{5 \pi}{12}+k \pi \end{array}(k \in \mathbb{Z}) .\right.\)

D. \(\left[\begin{array}{l} x=-\frac{\pi}{24}-\frac{k \pi}{2} \\ x=-\frac{ \pi}{12}+k \pi \end{array}(k \in \mathbb{Z}) .\right.\)