Tính đạo hàm của hàm số sau: \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2 % da9maalaaabaGaci4CaiaacMgacaGGUbGaaGOmaiaadIhacqGHRaWk % ciGGJbGaai4BaiaacohacaaIYaGaamiEaaqaaiaaikdaciGGZbGaai % yAaiaac6gacaaIYaGaamiEaiabgkHiTiGacogacaGGVbGaai4Caiaa % ikdacaWG4baaaiaac6caaaa!4D7F! y = \frac{{\sin 2x + \cos 2x}}{{2\sin 2x - \cos 2x}}.\)
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Lời giải:
Báo sai\(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiaacE % cacqGH9aqpdaWcaaqaamaabmaabaGaci4CaiaacMgacaGGUbGaaGOm % aiaadIhacqGHRaWkciGGJbGaai4BaiaacohacaaIYaGaamiEaaGaay % jkaiaawMcaamaaCaaaleqabaGaai4laaaakiaac6cadaqadaqaaiaa % ikdaciGGZbGaaiyAaiaac6gacaaIYaGaamiEaiabgkHiTiGacogaca % GGVbGaai4CaiaaikdacaWG4baacaGLOaGaayzkaaGaeyOeI0YaaeWa % aeaacaaIYaGaci4CaiaacMgacaGGUbGaaGOmaiaadIhacqGHsislci % GGJbGaai4BaiaacohacaaIYaGaamiEaaGaayjkaiaawMcaamaaCaaa % leqabaGaai4laaaakiaac6cadaqadaqaaiGacohacaGGPbGaaiOBai % aaikdacaWG4bGaey4kaSIaci4yaiaac+gacaGGZbGaaGOmaiaadIha % aiaawIcacaGLPaaaaeaadaqadaqaaiaaikdaciGGZbGaaiyAaiaac6 % gacaaIYaGaamiEaiabgkHiTiGacogacaGGVbGaai4CaiaaikdacaWG % 4baacaGLOaGaayzkaaWaaWbaaSqabeaacaaIYaaaaaaaaaa!79BE! y' = \frac{{{{\left( {\sin 2x + \cos 2x} \right)}^/}.\left( {2\sin 2x - \cos 2x} \right) - {{\left( {2\sin 2x - \cos 2x} \right)}^/}.\left( {\sin 2x + \cos 2x} \right)}}{{{{\left( {2\sin 2x - \cos 2x} \right)}^2}}}\)
\(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiaacE % cacqGH9aqpdaWcaaqaamaabmaabaGaaGOmaiGacogacaGGVbGaai4C % aiaaikdacaWG4bGaeyOeI0IaaGOmaiGacohacaGGPbGaaiOBaiaaik % dacaWG4baacaGLOaGaayzkaaWaaeWaaeaacaaIYaGaci4CaiaacMga % caGGUbGaaGOmaiaadIhacqGHsislciGGJbGaai4BaiaacohacaaIYa % GaamiEaaGaayjkaiaawMcaaiabgkHiTmaabmaabaGaaGinaiGacoga % caGGVbGaai4CaiaaikdacaWG4bGaey4kaSIaaGOmaiGacohacaGGPb % GaaiOBaiaaikdacaWG4baacaGLOaGaayzkaaWaaeWaaeaaciGGZbGa % aiyAaiaac6gacaaIYaGaamiEaiabgUcaRiGacogacaGGVbGaai4Cai % aaikdacaWG4baacaGLOaGaayzkaaaabaWaaeWaaeaacaaIYaGaci4C % aiaacMgacaGGUbGaaGOmaiaadIhacqGHsislciGGJbGaai4Baiaaco % hacaaIYaGaamiEaaGaayjkaiaawMcaamaaCaaaleqabaGaaGOmaaaa % aaaaaa!78BC! y' = \frac{{\left( {2\cos 2x - 2\sin 2x} \right)\left( {2\sin 2x - \cos 2x} \right) - \left( {4\cos 2x + 2\sin 2x} \right)\left( {\sin 2x + \cos 2x} \right)}}{{{{\left( {2\sin 2x - \cos 2x} \right)}^2}}}\)
\(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiaacE % cacqGH9aqpdaWcaaqaaiabgkHiTiaaiAdaciGGJbGaai4Baiaacoha % daahaaWcbeqaaiaaikdaaaGccaaIYaGaamiEaiabgkHiTiaaiAdaci % GGZbGaaiyAaiaac6gadaahaaWcbeqaaiaaikdaaaGccaaIYaGaamiE % aaqaamaabmaabaGaaGOmaiGacohacaGGPbGaaiOBaiaaikdacaWG4b % GaeyOeI0Iaci4yaiaac+gacaGGZbGaaGOmaiaadIhaaiaawIcacaGL % PaaadaahaaWcbeqaaiaaikdaaaaaaOGaeyypa0ZaaSaaaeaacqGHsi % slcaaI2aaabaWaaeWaaeaacaaIYaGaci4CaiaacMgacaGGUbGaaGOm % aiaadIhacqGHsislciGGJbGaai4BaiaacohacaaIYaGaamiEaaGaay % jkaiaawMcaamaaCaaaleqabaGaaGOmaaaaaaaaaa!644D! y' = \frac{{ - 6{{\cos }^2}2x - 6{{\sin }^2}2x}}{{{{\left( {2\sin 2x - \cos 2x} \right)}^2}}} = \frac{{ - 6}}{{{{\left( {2\sin 2x - \cos 2x} \right)}^2}}}\)
