Đạo hàm của hàm số \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2 % da9iabgkHiTmaalaaabaGaaGOmaaqaaiGacshacaGGHbGaaiOBamaa % bmaabaGaaGymaiabgkHiTiaaikdacaWG4baacaGLOaGaayzkaaaaaa % aa!416C! y = - \frac{2}{{\tan \left( {1 - 2x} \right)}}\) bằng:
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Lời giải:
Báo sai\(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGabmyEayaafa % Gaeyypa0JaeyOeI0IaaGOmaiaac6cadaWcaaqaaiabgkHiTmaabmaa % baGaciiDaiaacggacaGGUbWaaeWaaeaacaaIXaGaeyOeI0IaaGOmai % aadIhaaiaawIcacaGLPaaaaiaawIcacaGLPaaadaahaaWcbeqaaOGa % mai4gkdiIcaaaeaaciGG0bGaaiyyaiaac6gadaahaaWcbeqaaiaaik % daaaGcdaqadaqaaiaaigdacqGHsislcaaIYaGaamiEaaGaayjkaiaa % wMcaaaaacqGH9aqpcaaIYaGaeyyXIC9aaSaaaeaacqGHsislcaaIYa % GaeyyXIC9aaSaaaeaacaaIXaaabaGaci4yaiaac+gacaGGZbWaaWba % aSqabeaacaaIYaaaaOGaamiEaaaaaeaaciGG0bGaaiyyaiaac6gada % ahaaWcbeqaaiaaikdaaaGcdaqadaqaaiaaigdacqGHsislcaaIYaGa % amiEaaGaayjkaiaawMcaaaaacqGH9aqpdaWcaaqaaiabgkHiTiaais % daaeaaciGGZbGaaiyAaiaac6gadaahaaWcbeqaaiaaikdaaaGcdaqa % daqaaiaaigdacqGHsislcaaIYaGaamiEaaGaayjkaiaawMcaaaaaaa % a!722E! y' = - 2.\frac{{ - {{\left( {\tan \left( {1 - 2x} \right)} \right)}^\prime }}}{{{{\tan }^2}\left( {1 - 2x} \right)}} = 2 \cdot \frac{{ - 2 \cdot \frac{1}{{{{\cos }^2}x}}}}{{{{\tan }^2}\left( {1 - 2x} \right)}} = \frac{{ - 4}}{{{{\sin }^2}\left( {1 - 2x} \right)}}\)