Hàm số y = tan x – cot x có đạo hàm là:
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Lời giải:
Báo sai\(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiaacE % cacqGH9aqpdaWcaaqaaiaaigdaaeaaciGGJbGaai4Baiaacohadaah % aaWcbeqaaiaaikdaaaGccaWG4baaaiabgUcaRmaalaaabaGaaGymaa % qaaiGacohacaGGPbGaaiOBamaaCaaaleqabaGaaGOmaaaakiaadIha % aaGaeyypa0ZaaSaaaeaaciGGZbGaaiyAaiaac6gadaahaaWcbeqaai % aaikdaaaGccaWG4bGaey4kaSIaci4yaiaac+gacaGGZbWaaWbaaSqa % beaacaaIYaaaaOGaamiEaaqaaiGacohacaGGPbGaaiOBamaaCaaale % qabaGaaGOmaaaakiaadIhacaGGUaGaci4yaiaac+gacaGGZbWaaWba % aSqabeaacaaIYaaaaOGaamiEaaaacqGH9aqpdaWcaaqaaiaaisdaae % aaciGGZbGaaiyAaiaac6gadaahaaWcbeqaaiaaikdaaaGccaaIYaGa % amiEaaaaaaa!61BE! y' = \frac{1}{{{{\cos }^2}x}} + \frac{1}{{{{\sin }^2}x}} = \frac{{{{\sin }^2}x + {{\cos }^2}x}}{{{{\sin }^2}x.{{\cos }^2}x}} = \frac{4}{{{{\sin }^2}2x}}\)