Hàm số \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2 % da9maalaaabaGaaGymaaqaaiaaikdaaaWaaeWaaeaacaaIXaGaey4k % aSIaciiDaiaacggacaGGUbGaamiEaaGaayjkaiaawMcaamaaCaaale % qabaGaaGOmaaaaaaa!415B! y = \frac{1}{2}{\left( {1 + \tan x} \right)^2}\) có đạo hàm
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Lời giải:
Báo saita có \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiaacE % cacqGH9aqpdaWcaaqaaiaaigdaaeaacaaIYaaaaiaac6cacaaIYaWa % aeWaaeaacaaIXaGaey4kaSIaciiDaiaacggacaGGUbGaamiEaaGaay % jkaiaawMcaaiaac6cadaqadaqaaiaaigdacqGHRaWkciGG0bGaaiyy % aiaac6gacaWG4baacaGLOaGaayzkaaWaaWbaaSqabeaacaGGNaaaaa % aa!4B09! y' = \frac{1}{2}.2(1+tanx)(1+tanx)'\) \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaeyypa0Zaae % WaaeaacaaIXaGaey4kaSIaciiDaiaacggacaGGUbGaamiEaaGaayjk % aiaawMcaamaalaaabaGaaGymaaqaaiGacogacaGGVbGaai4CamaaCa % aaleqabaGaaGOmaaaakiaadIhaaaaaaa!437B! = \left( {1 + \tan x} \right)\frac{1}{{{{\cos }^2}x}}\) \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaeyypa0Zaae % WaaeaacaaIXaGaey4kaSIaciiDaiaacggacaGGUbGaamiEaaGaayjk % aiaawMcaamaabmaabaGaaGymaiabgUcaRiGacshacaGGHbGaaiOBam % aaCaaaleqabaGaaGOmaaaakiaadIhaaiaawIcacaGLPaaaaaa!45D4! = \left( {1 + \tan x} \right)\left( {1 + {{\tan }^2}x} \right)\)