Đạo hàm của hàm số \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamyEaiabg2 % da9iGacohacaGGPbGaaiOBamaaCaaaleqabaGaaGOmaaaakiaaikda % caWG4bGaaiOlaiGacogacaGGVbGaai4CaiaadIhacqGHRaWkdaWcaa % qaaiaaikdaaeaadaGcaaqaaiaadIhaaSqabaaaaaaa!44C3! y = {\sin ^2}2x.\cos x + \frac{2}{{\sqrt x }}\) là
Hãy suy nghĩ và trả lời câu hỏi trước khi xem đáp án
Lời giải:
Báo sai\(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGabmyEayaafa % Gaeyypa0JaaGOmaiGacohacaGGPbGaaiOBaiaaikdacaWG4bGaaiOl % aiGacogacaGGVbGaai4CaiaaikdacaWG4bGaaiOlaiGacogacaGGVb % Gaai4CaiaadIhacqGHRaWkciGGZbGaaiyAaiaac6gadaahaaWcbeqa % aiaaikdaaaGccaaIYaGaamiEaiaac6cadaqadaqaaiabgkHiTiGaco % hacaGGPbGaaiOBaiaadIhaaiaawIcacaGLPaaacqGHsisldaWcaaqa % aiaaigdaaeaacaWG4bWaaOaaaeaacaWG4baaleqaaaaakiabg2da9i % GacohacaGGPbGaaiOBaiaaisdacaWG4bGaaiOlaiGacogacaGGVbGa % ai4CaiaadIhacqGHsislciGGZbGaaiyAaiaac6gadaahaaWcbeqaai % aaikdaaaGccaaIYaGaamiEaiaac6caciGGZbGaaiyAaiaac6gacaWG % 4bGaeyOeI0YaaSaaaeaacaaIXaaabaGaamiEamaakaaabaGaamiEaa % Wcbeaaaaaaaa!712B! y' = 2\sin 2x.\cos 2x.\cos x + {\sin ^2}2x.\left( { - \sin x} \right) - \frac{1}{{x\sqrt x }} = \sin 4x.\cos x - {\sin ^2}2x.\sin x - \frac{1}{{x\sqrt x }}\)