Trắc nghiệm Khảo sát sự biến thiên và vẽ đồ thị của hàm số Toán Lớp 12

A. 6

B. 2

C. 4

D. 3

A. Với mọi $% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVC0xf9qq1qpepC0xbbL8F4rqGqFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaciaabeqaamaabiabcaGcbaGaamiEamaaBa % aaleaacaaIXaaabeaakiaacYcacaWG4bWaaSbaaSqaaiaaikdaaeqa % aOGaeyicI4SaeSyhHeQaaeiiaiabgkDiElaadAgadaqadaqaaiaadI % hadaWgaaWcbaGaaGymaaqabaaakiaawIcacaGLPaaacqGH8aapcaWG % MbWaaeWaaeaacaWG4bWaaSbaaSqaaiaaikdaaeqaaaGccaGLOaGaay % zkaaaaaa!49AC! {x_1},{x_2} \in R{\rm{ }} \Rightarrow f\left( {{x_1}} \right) < f\left( {{x_2}} \right)$

B. Với mọi $% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVC0xf9qq1qpepC0xbbL8F4rqGqFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaciaabeqaamaabiabcaGcbaGaamiEamaaBa % aaleaacaaIXaaabeaakiabgYda8iaadIhadaWgaaWcbaGaaGOmaaqa % baGccqGHiiIZcqWIDesOcaqGGaGaeyO0H4TaamOzamaabmaabaGaam % iEamaaBaaaleaacaaIXaaabeaaaOGaayjkaiaawMcaaiabgYda8iaa % dAgadaqadaqaaiaadIhadaWgaaWcbaGaaGOmaaqabaaakiaawIcaca % GLPaaaaaa!4A00! {x_1} < {x_2} \in R {\rm{ }} \Rightarrow f\left( {{x_1}} \right) < f\left( {{x_2}} \right)$

C. Với mọi $% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVC0xf9qq1qpepC0xbbL8F4rqGqFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaciaabeqaamaabiabcaGcbaGaamiEamaaBa % aaleaacaaIXaaabeaakiaacYcacaWG4bWaaSbaaSqaaiaaikdaaeqa % aOGaeyicI4SaeSyhHeQaaeiiaiabgkDiElaadAgadaqadaqaaiaadI % hadaWgaaWcbaGaaGymaaqabaaakiaawIcacaGLPaaacqGH+aGpcaWG % MbWaaeWaaeaacaWG4bWaaSbaaSqaaiaaikdaaeqaaaGccaGLOaGaay % zkaaaaaa!49B0! {x_1},{x_2} \in R {\rm{ }} \Rightarrow f\left( {{x_1}} \right) > f\left( {{x_2}} \right)$

D. Với mọi $% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVC0xf9qq1qpepC0xbbL8F4rqGqFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaciaabeqaamaabiabcaGcbaGaamiEamaaBa % aaleaacaaIXaaabeaakiabg6da+iaadIhadaWgaaWcbaGaaGOmaaqa % baGccqGHiiIZcqWIDesOcaqGGaGaeyO0H4TaamOzamaabmaabaGaam % iEamaaBaaaleaacaaIXaaabeaaaOGaayjkaiaawMcaaiabgYda8iaa % dAgadaqadaqaaiaadIhadaWgaaWcbaGaaGOmaaqabaaakiaawIcaca % GLPaaaaaa!4A04! {x_1} > {x_2} \in R{\rm{ }} \Rightarrow f\left( {{x_1}} \right) < f\left( {{x_2}} \right)$

A. Nếu $% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGacaGaaiaabeqaamaabaabaaGcbaGabmOzayaafa % WaaeWaaeaacaWG4baacaGLOaGaayzkaaGaeyyzImRaaGimaiaaykW7 % caaMc8UaeyiaIiIaamiEaiabgIGiopaabmaabaGaamyyaiaacUdaca % WGIbaacaGLOaGaayzkaaaaaa!466B! f'\left( x \right) \ge 0\,\,\forall x \in \left( {a;b} \right)$ thì hàm số y = f(x)  đồng biến trên (a;b).

B. Nếu $% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGacaGaaiaabeqaamaabaabaaGcbaGabmOzayaafa % WaaeWaaeaacaWG4baacaGLOaGaayzkaaGaeyOpa4JaaGimaiaaykW7 % caaMc8UaeyiaIiIaamiEaiabgIGiopaabmaabaGaamyyaiaacUdaca % WGIbaacaGLOaGaayzkaaaaaa!45AD! f'\left( x \right) > 0\,\,\forall x \in \left( {a;b} \right)$ thì hàm số y = f(x) đồng biến trên (a,b).

C. Hàm số y = f(x)  đồng biến trên (a,b) khi và chỉ khi $% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGacaGaaiaabeqaamaabaabaaGcbaGabmOzayaafa % WaaeWaaeaacaWG4baacaGLOaGaayzkaaGaeyyzImRaaGimaiaaykW7 % caaMc8UaeyiaIiIaamiEaiabgIGiopaabmaabaGaamyyaiaacUdaca % WGIbaacaGLOaGaayzkaaaaaa!466B! f'\left( x \right) \ge 0\,\,\forall x \in \left( {a;b} \right)$ .

D. Hàm số y = f(x) đồng biến trên (a,b) khi và chỉ khi $% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGacaGaaiaabeqaamaabaabaaGcbaGabmOzayaafa % WaaeWaaeaacaWG4baacaGLOaGaayzkaaGaeyOpa4JaaGimaiaaykW7 % caaMc8UaeyiaIiIaamiEaiabgIGiopaabmaabaGaamyyaiaacUdaca % WGIbaacaGLOaGaayzkaaaaaa!45AD! f'\left( x \right) > 0\,\,\forall x \in \left( {a;b} \right)$

A. Hàm số f(x) đồng biến trên (a;b) khi và chỉ khi $% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGabmOzayaafa % WaaeWaaeaacaWG4baacaGLOaGaayzkaaGaeyyzImRaaGimaiaacYca % cqGHaiIicaWG4bGaeyicI48aaeWaaeaacaWGHbGaai4oaiaadkgaai % aawIcacaGLPaaaaaa!4407! f'\left( x \right) \ge 0,\forall x \in \left( {a;b} \right)$

B. Hàm số f(x) đồng biến trên (a;b) khi và chỉ khi $% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGabmOzayaafa % WaaeWaaeaacaWG4baacaGLOaGaayzkaaGaeyipaWJaaGimaiaacYca % cqGHaiIicaWG4bGaeyicI48aaeWaaeaacaWGHbGaai4oaiaadkgaai % aawIcacaGLPaaaaaa!4345! f'\left( x \right) < 0,\forall x \in \left( {a;b} \right)$

C. Hàm số f(x) đồng biến trên (a;b) khi và chỉ khi $% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGabmOzayaafa % WaaeWaaeaacaWG4baacaGLOaGaayzkaaGaeyizImQaaGimaiaacYca % cqGHaiIicaWG4bGaeyicI48aaeWaaeaacaWGHbGaai4oaiaadkgaai % aawIcacaGLPaaaaaa!43F6! f'\left( x \right) \le 0,\forall x \in \left( {a;b} \right)$

D. Hàm số f(x) đồng biến trên (a;b) khi và chỉ khi $% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGabmOzayaafa % WaaeWaaeaacaWG4baacaGLOaGaayzkaaGaeyyzImRaaGimaiaacYca % cqGHaiIicaWG4bGaeyicI48aaeWaaeaacaWGHbGaai4oaiaadkgaai % aawIcacaGLPaaaaaa!4407! f'\left( x \right) \ge 0,\forall x \in \left( {a;b} \right)$ và $% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGabmOzayaafa % WaaeWaaeaacaWG4baacaGLOaGaayzkaaGaeyypa0JaaGimaaaa!3B31! f'\left( x \right) = 0$ tại hữu hạn giá trị $% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabgI % GiopaabmaabaGaamyyaiaacUdacaWGIbaacaGLOaGaayzkaaaaaa!3C8A! x \in \left( {a;b} \right)$

A. 3

B. 1

C. 2

D. 4

A. 2

B. 3

C. 1

D. 0

A. 8

B. 4

C. 10

D. 9

A. 0

B. 1

C. 2

D. 3

A. 2

B. 4

C. 1

D. 3

A. 1

B. 3

C. 4

D. 2

A. 3

B. 5

C. 1

D. 2

A. 1

B. 3

C. 2

D. 0

A. 2

B. 3

C. 0

D. 1

A. 4

B. 3

C. 2

D. 1

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B.

C.

D.

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C.

D.

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B.

C.

D.

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D.

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D.

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C.

D.

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B.

C.

D.

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C.

D.

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C.

D.

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D.

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D.

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B.

C.

D.

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D.

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D.

A.

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C.

D.

A.  

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D.

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D.

A.

B.

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D.

A. $y=\frac{2x+1}{x+1}$

B. $y=\frac{x-1}{x+1}$

C. $y=\frac{x+2}{x+1}$

D. $y=\frac{x+3}{1-x}$

A. $y=\frac{x+1}{x-1}$

B. $y=\frac{2x+1}{x-1}$

C. $y=\frac{x+2}{x-1}$

D. $y=\frac{x+2}{1-x}$

A. $y=\frac{x+1}{x-1}$

B. $y=\frac{x-1}{x+1}$

C. $y=\frac{2x+1}{2x-2}$

D. $y=\frac{-x}{1-x}$

A. $y=\frac{3x-1}{1-x}$

B. $y=\frac{3x+1}{1-2x}$

C. $y=\frac{3x-1}{-1-2x}$

D. $y=\frac{3x-2}{1-x}$

A. $y=4-\frac{x^4}{4}$

B. $y = 4 - x²$

C. $y=4-\frac{x^2}{2}-\frac{x^4}{8}$

D. $y=4-\frac{x^2}{4}-\frac{x^4}{16}$

A. $y = x⁴ - 4x³ + 4x²$

B. $y = x² - 4x + 4$

C. $y = -x⁴ + 4x³ - 4x²$

D. $y = -x² + 4x - 4$

A. $y = -x ^4 + 8x^ 2 + 1$

B. $y = x^4 - 8x^2 + 1$

C. $y = -x^3 + 3x^2 + 1$

D. $y = | x| ³ - 3x^ 2 + 1$

A. $y = x⁴ - 2x² -3$

B. $y = x⁴ + 2x² -3$

C. $y = -x⁴ + 2x² +3$

D. $y = - x⁴ - 2x² + 3$

A. $y = x⁴ - 2x² -1.$

B. $y = -x⁴ + 2x² -1$

C. $y = x⁴ + 2x² -1$

D. $y = \frac{x^4}{4} + 2x² -1$

A. $y = x² -1$

B. $y = x⁴ + 2x² -1$

C. $y = -x⁴ - 2x² -1$

D. $y = x³ + 2x² -1$

A. $y = -x⁴ + 4x ² .$

B. $y = -x ⁴ - 2x ² .$

C. $y = x ⁴ - 3x ² .$

D. $y = -\frac{1}{4}x ⁴ + 3x ²$

A. $y = x⁴ - 2x² -1.$

B. $y = x⁴ - 2x² +1.$

C. $y = x⁴ - 2x²$

D. $y = x⁴ - 2x² +2$

A. $y = -x³ + 3x +1.$

B. $y = x⁴ - 2x² +1.$

C. $y = x³ -3x +1.$

D. $y = x^3 - 3x² +1.$

A. $y = x³ + 3x +1$

B. $y = x³ -3x +1$

C. $y = -x³ -3x +1$

D. $y = -x³ + 3x +1$

A. $y = x³ - 3x² +1$

B. $y = x³ +x² +1$

C. $y = -x³+3x² +1$

D. $y = x³ + 3x +1$

A. $y = -x⁴ - x² -1$

B. $y = x⁴ - 2x² -1$

C. $. y = - \frac{1}{3} x³ + x² -1$

D. $. y = \frac{1}{3} x³ -2x² +2$

A. $y=f(x)=x^3-3x+1$

B. $y=f(x)=x^3-3x-1$

C. $y=f(x)=-x^3+3x+1$

D. $y=f(x)=-x^3+3x-1$

A. $y=x^3-3x^2+1$

B. $y=-\frac{x^3}{3}+x^2+1$

C. $y=2x^3-6x^2+1$

D. $y=-x^3-3x^2+1$