Trắc nghiệm Hàm số lũy thừa Toán Lớp 12

A. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiabg2 % da9maajibabaGaeyOeI0IaaGOmaiaacUdacqGHsisldaWcaaqaaiaa % iodaaeaacaaIYaaaaaGaay5waiaawMcaaaaa!3E82! S = \left[ { - 2; - \frac{3}{2}} \right)\)

B. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiabg2 % da9maajibabaGaeyOeI0IaaGOmaiaacUdacaaIWaaacaGLBbGaayzk % aaaaaa!3CC6! S = \left[ { - 2;0} \right)\)

C. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiabg2 % da9maajadabaGaeyOeI0IaeyOhIuQaai4oaiaaikdaaiaawIcacaGL % Dbaaaaa!3D9C! S = \left( { - \infty ;2} \right]\)

D. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiabg2 % da9iabl2riHkaacYfadaWadaqaaiabgkHiTmaalaaabaGaaG4maaqa % aiaaikdaaaGaai4oaiaaicdaaiaawUfacaGLDbaaaaa!4002! S = R\backslash \left[ { - \frac{3}{2};0} \right]\)

A. (1;2)

B. (1;2]

C. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaKamaeaacq % GHsislcqGHEisPcaGG7aGaaGOmaaGaayjkaiaaw2faaaaa!3BBE! \left( { - \infty ;2} \right]\)

D. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaKGeaeaaca % aIYaGaai4oaiabgUcaRiabg6HiLcGaay5waiaawMcaaaaa!3B94! \left[ {2; + \infty } \right)\)

A. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaeWaaeaacq % GHsislcqGHEisPcaGG7aGaaGPaVlaaykW7caaIXaaacaGLOaGaayzk % aaaaaa!3E6A! \left( { - \infty ;\,\,1} \right)\)

B. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaKGeaeaaca % aIWaGaai4oaiaaykW7caaMc8UaaGymaaGaay5waiaawMcaaiabgQIi % ipaajadabaGaaGOmaiaacUdacaaMc8UaaGPaVlaaiodaaiaawIcaca % GLDbaaaaa!45F0! \left[ {0;\,\,1} \right) \cup \left( {2;\,\,3} \right]\)

C. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaKGeaeaaca % aIWaGaai4oaiaaykW7caaMc8UaaGOmaaGaay5waiaawMcaaiabgQIi % ipaajadabaGaaG4maiaacUdacaaMc8UaaGPaVlaaiEdaaiaawIcaca % GLDbaaaaa!45F6! \left[ {0;\,\,2} \right) \cup \left( {3;\,\,7} \right]\)

D. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaKGeaeaaca % aIWaGaai4oaiaaykW7caaMc8UaaGOmaaGaay5waiaawMcaaaaa!3D11! \left[ {0;\,\,2} \right)\)

A. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiabg2 % da9maabmaabaGaaGymaiaacUdacaaMe8UaaGymaiabgUcaRmaakaaa % baGaaGOmaaWcbeaaaOGaayjkaiaawMcaaaaa!3EE0! S = \left( {1;\;1 + \sqrt 2 } \right)\)

B. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiabg2 % da9maabmaabaGaaGymaiaacUdacaaMe8UaaGyoaaGaayjkaiaawMca % aaaa!3D25! S = \left( {1;\;9} \right)\)

C. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiabg2 % da9maabmaabaGaaGymaiabgUcaRmaakaaabaGaaGOmaaWcbeaakiaa % cUdacaaMe8Uaey4kaSIaeyOhIukacaGLOaGaayzkaaaaaa!4078! S = \left( {1 + \sqrt 2 ;\; + \infty } \right)\)

D. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiabg2 % da9maabmaabaGaaGyoaiaacUdacaaMe8Uaey4kaSIaeyOhIukacaGL % OaGaayzkaaaaaa!3EBD! S = \left( {9;\; + \infty } \right)\)

A. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaKGeaeaada % GcaaqaaiaaikdaaSqabaGccaGG7aGaey4kaSIaeyOhIukacaGLBbGa % ayzkaaGaaiOlaaaa!3C6C! \left[ {\sqrt 2 ; + \infty } \right).\)

B. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaKGeaeaacq % GHsisldaGcaaqaaiaaikdaaSqabaGccaGG7aGaaGimaaGaay5waiaa % wMcaaiabgQIiipaajadabaGaaGimaiaacUdadaGcaaqaaiaaikdaaS % qabaaakiaawIcacaGLDbaacaGGUaaaaa!41AB! \left[ { - \sqrt 2 ;0} \right) \cup \left( {0;\sqrt 2 } \right].\)

C. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaamWaaeaacq % GHsisldaGcaaqaaiaaikdaaSqabaGccaGG7aWaaOaaaeaacaaIYaaa % leqaaaGccaGLBbGaayzxaaGaaiOlaaaa!3C06! \left[ { - \sqrt 2 ;\sqrt 2 } \right].\)

D. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaKamaeaaca % aIWaGaai4oamaakaaabaGaaGOmaaWcbeaaaOGaayjkaiaaw2faaiaa % c6caaaa!3AF2! \left( {0;\sqrt 2 } \right].\)

A. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiabg2 % da9maabmqabaWaaSaaaeaacaaIXaaabaGaaGOmaaaacaGG7aGaaGPa % VpaalaaabaGaaGynaaqaaiaaikdaaaaacaGLOaGaayzkaaaaaa!3EB8! S = \left( {\frac{1}{2};\,\frac{5}{2}} \right)\)

B. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiabg2 % da9maajibabaWaaSaaaeaacaaIXaaabaGaaGOmaaaacaGG7aGaaGPa % VpaalaaabaGaaGynaaqaaiaaikdaaaaacaGLBbGaayzkaaaaaa!3F01! S = \left[ {\frac{1}{2};\,\frac{5}{2}} \right)\)

C. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiabg2 % da9maabmqabaGaeyOeI0IaeyOhIuQaai4oaiaaykW7daWcaaqaaiaa % iwdaaeaacaaIYaaaaaGaayjkaiaawMcaaaaa!3F8F! S = \left( { - \infty ;\,\frac{5}{2}} \right)\)

D. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaam4uaiabg2 % da9maabmqabaWaaSaaaeaacaaI1aaabaGaaGOmaaaacaGG7aGaaGPa % VlabgUcaRiabg6HiLcGaayjkaiaawMcaaaaa!3F84! S = \left( {\frac{5}{2};\, + \infty } \right)\)

A. (8;16)

B. (0;16)

C. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaeWaaeaaca % aI4aGaai4oaiabgUcaRiabg6HiLcGaayjkaiaawMcaaaaa!3B50! \left( {8; + \infty } \right)\)

D. R

A. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaSaaaeaaca % aIXaaabaGaaGOmaaaacqGH8aapcaWG4bGaeyipaWZaaSaaaeaacaaI % YaGaaGynaaqaaiaaiodacaaIYaaaaaaa!3D84! \frac{1}{2} < x < \frac{{25}}{{32}}\)

B. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg6 % da+maalaaabaGaaGOmaiaaiwdaaeaacaaIZaGaaGOmaaaaaaa!3AFD! x > \frac{{25}}{{32}}\)

C. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabgY % da8maalaaabaGaaGymaaqaaiaaikdaaaaaaa!397C! x < \frac{1}{2}\) hoặc \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg6 % da+maalaaabaGaaGOmaiaaiwdaaeaacaaIZaGaaGOmaaaaaaa!3AFD! x > \frac{{25}}{{32}}\)

D. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiEaiabg6 % da+maalaaabaGaaGymaaqaaiaaikdaaaaaaa!3980! x > \frac{1}{2}\)

A. \( \left( {1;\frac{3}{2}} \right)\)

B. \( \left( {\frac{3}{2}; + \infty } \right)\)

C. \(\left( {\frac{1}{2};\frac{3}{2}} \right)\)

D. \(\left( { - \infty ;\frac{3}{2}} \right)\)

A. R \ {1}

B. R

C. {1}

D. \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaeyybIymaaa!376D! \emptyset \)

A. \(\begin{array}{l} M\left( { - 1; - \frac{1}{3}} \right) \end{array}\)

B. \(M\left( { - 1;\frac{1}{3}} \right)\)

C. \(M\left( {1;\frac{1}{3}} \right)\)

D. \(M\left( {1; - \frac{1}{3}} \right)\)

A. \(y=-x^2+2x+1\)

B. \(y=log_{0,5}x\)

C. \(y=\frac{1}{2^x}\)

D. \(y=2^x\)

A. \(\begin{array}{l} y = {\left( {\frac{1}{2}} \right)^x} \end{array}\)

B. \(y = {x^2}\)

C. \(y = {\log _2}x\)

D. \(y = {2^x}\)

A. \(\begin{array}{l} y = {\log _{0,5}}x \end{array}\)

B. \(y = {\log _{\sqrt 7 }}x\)

C. \(y = {e^x}\)

D. \(y = {e^{ - x}}\)

A. \(0<\beta<1<\alpha\)

B. \(\beta<0<1<\alpha\)

C. \(0<\alpha<1<\beta\)

D. \(\alpha<0<1<\beta\)

A. Đồ thị hàm số không cắt trục hoành  

B. Hàm số nghịch biến  trên \((0;+\infty)\)

C. Hàm số có tập xác định là \((0;+\infty)\)

D. Đồ thị hàm số không có tiệm cận

A. Đồ thị hàm số nhận Ox, Oy làm hai tiệm cận.

B. Đồ thị hàm số luôn đi qua M(1;1)

C. Hàm số luôn đồng biến trên \((0;+\infty)\)

D. Tập xác định của hàm số là \(D=(0;+\infty)\)

A. Có một tiệm cận ngang và một tiệm cận đứng.

B. Không có tiệm cận ngang và có một tiệm cận đứng.

C. Có một tiệm cận ngang và không có tiệm cận đứng.

D. Không có tiệm cận

A. Số a

B. Số a và số c

C. Số b

D. Số c

A. \(y=x^3\)

B. \(y=x^4\)

C. \(y=x^{1\over5}\)

D. \(y=\sqrt x\)

A. \(\begin{array}{l} y' = \frac{2}{{x\ln 2x.\ln 10}} \end{array}\)

B. \(y' = \frac{1}{{x\ln 2x.\ln 10}}\)

C. \(y' = \frac{1}{{2x\ln 2x.\ln 10}}\)

D. \(y' = \frac{1}{{x\ln 2x}}\)

A. \(ln2\over2\)

B. 1

C. \(1\over2\)

D. 2

A. \(1\over 3\)

B. \({1\over 3ln3}+2\)

C. \({1\over 3ln3}-1\)

D. \({1\over 3ln3}\)

A. 8

B. -4

C. 2

D. 5

A. \(\begin{array}{l} y' = \frac{{ - 2\cos x}}{{2\sin x - 1}} \end{array}\)

B. \(y' = \frac{{2\cos x}}{{2\sin x - 1}}\)

C. \(y' = \frac{{2\cos x}}{{\left( {2\sin x - 1} \right)\ln 10}}\)

D. \(y' = \frac{{ - 2\cos x}}{{\left( {2\sin x - 1} \right)\ln 10}}\)

A. \(\begin{array}{l} \frac{{2x - 3}}{{\left( {{x^2} - 3x - 4} \right)\ln 8}} \end{array}\)

B. \(\frac{{2x - 3}}{{\left( {{x^2} - 3x - 4} \right)\ln 2}}\)

C. \(\frac{{2x - 3}}{{\left( {{x^2} - 3x - 4} \right)}}\)

D. \(\frac{1}{{\left( {{x^2} - 3x - 4} \right)\ln 8}}\)

A. f'(3)=-1,5

B. f'(2)=0

C. f'(5)=1,2

D. f'(-1)=-1,2

A. \(\begin{array}{l} y' = \frac{{2x}}{{2017}} \end{array}\)

B. \(y' = \frac{{2x}}{{\left( {{x^2} + 1} \right)\ln 2017}}\)

C. \(y' = \frac{1}{{\left( {{x^2} + 1} \right)\ln 2017}}\)

D. \(y' = \frac{1}{{\left( {{x^2} + 1} \right)}}\)

A. \(\begin{array}{l} y' = \frac{1}{{\left( {4x + 1} \right)\ln 3}} \end{array}\)

B. \(y' = \frac{4}{{\left( {4x + 1} \right)\ln 3}}\)

C. \(y' = \frac{{\ln 3}}{{\left( {4x + 1} \right)}}\)

D. \(y' = \frac{{4\ln 3}}{{4x + 1}}\)

A. \(\begin{array}{l} y' = \frac{{7.\sqrt[{24}]{{{x^7}}}}}{{24}} \end{array}\)

B. \(y' = \frac{{14.\sqrt[{24}]{{{x^7}}}}}{{24}}\)

C. \(y' = \frac{{17}}{{24.\sqrt[{24}]{{{x^7}}}}}\)

D. \(y' = \frac{7}{{24.\sqrt[{24}]{{{x^7}}}}}\)

A. \(\begin{array}{l} y''(1) = {\ln ^2}\pi \end{array}\)

B. \(y''(1) = \pi \ln \pi \)

C. \(y''(1) = 0\)

D. \(y''(1) = \pi \left( {\pi - 1} \right)\)

A. \(\begin{array}{l} y' = \frac{{10x - 1}}{{3.\sqrt[3]{{5{x^2} - x + 2}}}} \end{array}\)

B. \(y' = \frac{{10x - 1}}{{\sqrt[3]{{{{\left( {5{x^2} - x + 2} \right)}^2}}}}}\)

C. \(y' = \frac{{10x - 1}}{{3.\sqrt[3]{{{{\left( {5{x^2} - x + 2} \right)}^2}}}}}\)

D. \(y' = \frac{1}{{3.\sqrt[3]{{5{x^2} - x + 2}}}}\)

A. \(a\ne 1 \,\,\rm{và}\,\,0<a<2\)

B. a>1

C. a<0

D. \(a\ne1 \,\,\rm{và}\,\,a>{1\over2}\)

A. 0

B. 2

C. 1

D. 2

A. \((-\infty;1)\)

B. (0;1)

C. \((1;+\infty)\)

D. (1;2)

A. \((-\infty;1)\)

B. \((1;+\infty)\)

C. \(\left( {\frac{1}{2};1} \right)\)

D. \(\left( { - \frac{1}{2}; + \infty } \right)\)

A. \(e\)

B. \(2e\)

C. 1

D. -1

A. 0

B. 2

C. 1

D. 3

A. \(\begin{array}{l} y = {\log _2}x \end{array}\)

B. \(y = {x^2} + {\log _2}x\)

C. \(y = x + {\log _2}x\)

D. \(y = {\log _2}\frac{1}{x}\)

A. \(\begin{array}{l} y = {\left( {\frac{\pi }{4}} \right)^x} \end{array}\)

B. \(y = \frac{1}{{{{\left( {\sqrt 7 - \sqrt 5 } \right)}^x}}}\)

C. \(y = \frac{1}{{{5^x}}}\)

D. \(y = {\left( {\frac{e}{3}} \right)^x}\)

A. \(y=x+log_2x\)

B. \(y=x+log_2{\frac{1}{x}}\)

C. \(y=x^2+log_2x\)

D. \(y=-log_2x\)

A. \(\begin{array}{l} y = {\left( {\frac{\pi }{4}} \right)^x} \end{array}\)

B. \(y = {\left( {\frac{2}{e}} \right)^x}\)

C. \(y = {\left( {\frac{2}{{\sqrt 3 + 1}}} \right)^x}\)

D. \(y = {\left( {\frac{{e + 1}}{\pi }} \right)^x}\)

A. Hàm số đã cho đồng biến trên khoảng \((-\infty;+\infty)\)

B. Hàm số đã cho nghịch biến trên khoảng \((-\infty;0)\)

C. Hàm số đã cho nghịch biến trên khoảng \((-\infty;+\infty)\)

D. Hàm số đã cho nghịch biến trên khoảng \((0;+\infty)\)

A. \(y=(\frac{1}{\pi})^x\)

B. \(\begin{array}{l} y = {\left( {\frac{2}{3}} \right)^x} \end{array}\)

C. \(y = {\left( {\sqrt 3 } \right)^x}\)

D. \(y = {\left( {0,5} \right)^x}\)

A. Hàm số luôn đồng biến trên \(\mathbb{R}\)  

B. Hàm số luôn nghịch biến trên khoảng \((-\infty;1)\)

C. Hàm số luôn đồng biến trên trên \((-\infty;1)\)

D. Hàm số luôn nghịch biến trên \(\mathbb{R}\)

A. \(\begin{array}{l} y = {\log _{\frac{e}{\pi }}}x \end{array}\)

B. \(y = {\log _{\sqrt 3 }}x\)

C. \(y = {\lg _2}x\)

D. \(y = log_{\pi}x\)

A. \(y=log_2{(1-x)}\)

B. \(y=2017^{2-x}\)

C. \(y=log_{\frac{1}{2}}{(3-x)}\)

D. \(y = {\left( {\frac{{\sqrt 3 }}{2}} \right)^{x + 1}}\)

A. \(y=logx\)

B. \(y=lnx\)

C. \(y=-logx\)

D. \(y=10^x\)

A. Đạo hàm của hàm số là \(y'=\frac{1}{xln2}\)

B. Đồ thị hàm số nhận trục Oy  làm tiệm cận đứng.

C. Tập xác định của hàm số là  \((-\infty;+\infty)\)

D. Hàm số đồng biến trên khoảng \((0;+\infty)\)

A. Hàm số đã cho đồng biến trên tập xác định.  

B. Đồ thị hàm số đã cho không có tiệm cận ngang.

C. Đồ thị hàm số đã cho có một tiệm cận đứng là trục Oy

D. Hàm số đã cho có tập xác định \(D=\mathbb{R}\backslash{\{0\}}\)