Tìm miền giá trị của hàm số \[f\left( x \right) = \sqrt {\arctan x - \frac{\pi }{4}} \]

12 m

15 m

17 m

19 m

\[g\left( x \right) = \sqrt[3]{{2{x^2} + {x^3}}}\]

\[g\left( x \right) = \sqrt[3]{{ - 2{x^2} + {x^3}}}\]

\[g\left( x \right) = \sqrt[3]{{{x^2}\left( {x - 2} \right)}}\]

\[g\left( x \right) = \sqrt[3]{{2{x^2} - {x^3}}}\]

$\left[e^{\frac{-\mathrm{\pi }}{2}},e^{\frac{\pi }{2}}\right]$

$(0,+\infty )$

(0,1]

$[e^{-1},e]$

_{$\frac{1}{12}$}

$\frac{5}{6}$

$\frac{1}{10}$

_{$\frac{1}{120}$}

\[\left( { - \infty ;1} \right)\]

\[\left( { - \infty ;0} \right)\]

\[\left[ {1; + \infty } \right)\]

\[\left[ {0; + \infty } \right)\]

\[{\alpha _1}\left( x \right) = \sin 2x - 2\sin x\]

\[{\alpha _3}\left( x \right) = {e^{\sin x}} - \cos x\]

\[{\alpha _4}\left( x \right) = \sqrt {1 + 2x} - 1 - \sqrt x \]

\[{\alpha _2}\left( x \right) = \arcsin \left( {\sqrt {4 + {x^2}} - 2} \right)\]

\[\alpha \left( x \right) = 1 - {\cos ^3}x\]

\[\chi \left( x \right) = \arctan \left( {\sqrt[3]{{8 + {x^4}}} - 2} \right)\]

\[\gamma \left( x \right) = \arcsin \left( {\sqrt {4 + {x^2}} - 2} \right)\]

Cả A, B, C đều sai