Hàm số nào sau đây không là nguyên hàm của hàm số \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOzaiaacI % cacaWG4bGaaiykaiabg2da9maalaaabaGaamiEaiaacIcacaWG4bGa % ey4kaSIaaGOmaiaacMcaaeaacaGGOaGaamiEaiabgUcaRiaaigdaca % GGPaWaaWbaaSqabeaacaaIYaaaaaaaaaa!4418! f(x) = \frac{{x(x + 2)}}{{{{(x + 1)}^2}}}\) ?
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Lời giải:
Báo saiVì \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGabmOrayaafa % GaaiikaiaadIhacaGGPaGaeyypa0ZaaeWaaeaadaWcaaqaaiaadIha % daahaaWcbeqaaiaaikdaaaGccqGHRaWkcaWG4bGaeyOeI0IaaGymaa % qaaiaadIhacqGHRaWkcaaIXaaaaaGaayjkaiaawMcaamaaCaaaleqa % baGccWaGGBOmGikaaiabg2da9maalaaabaGaamiEamaaCaaaleqaba % GaaGOmaaaakiabgUcaRiaaikdacaWG4bGaey4kaSIaaGOmaaqaamaa % bmaabaGaamiEaiabgUcaRiaaigdaaiaawIcacaGLPaaadaahaaWcbe % qaaiaaikdaaaaaaaaa!533B! F'(x) = {\left( {\frac{{{x^2} + x - 1}}{{x + 1}}} \right)^\prime } = \frac{{{x^2} + 2x + 2}}{{{{\left( {x + 1} \right)}^2}}}\)
Do đó \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOraiaacI % cacaWG4bGaaiykaiabg2da9maalaaabaGaamiEamaaCaaaleqabaGa % aGOmaaaakiabgUcaRiaadIhacqGHsislcaaIXaaabaGaamiEaiabgU % caRiaaigdaaaaaaa!423C! F(x) = \frac{{{x^2} + x - 1}}{{x + 1}}\)