Điều kiện xác định của bất phương trình \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaciiBaiaac+ % gacaGGNbWaaSbaaSqaamaalaaabaGaaGymaaqaaiaaikdaaaaabeaa % kiaacIcacaaI0aGaamiEaiabgUcaRiaaikdacaGGPaGaeyOeI0Iaci % iBaiaac+gacaGGNbWaaSbaaSqaamaalaaabaGaaGymaaqaaiaaikda % aaaabeaakiaacIcacaWG4bGaeyOeI0IaaGymaiaacMcacqGH+aGpca % GGSbGaai4BaiaacEgadaWgaaWcbaWaaSaaaeaacaaIXaaabaGaaGOm % aaaaaeqaaOGaamiEaaaa!4F3B! {\log _{\frac{1}{2}}}(4x + 2) - {\log _{\frac{1}{2}}}(x - 1) > lo{g_{\frac{1}{2}}}x\) là:
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Lời giải:
Báo saiBPT xác định khi : \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaiqaaqaabe % qaaiaadIhacqGH+aGpcaaIWaaabaGaaGinaiaadIhacqGHRaWkcaaI % YaGaeyOpa4JaaGimaaqaaiaadIhacqGHsislcaaIXaGaeyOpa4JaaG % imaaaacaGL7baacqGHuhY2daGabaabaeqabaGaamiEaiabg6da+iaa % icdaaeaacaWG4bGaeyOpa4JaeyOeI0YaaSaaaeaacaaIXaaabaGaaG % OmaaaaaeaacaWG4bGaeyOpa4JaaGymaaaacaGL7baacqGHuhY2caWG % 4bGaeyOpa4JaaGymaaaa!55E9! \left\{ \begin{array}{l} x > 0\\ 4x + 2 > 0\\ x - 1 > 0 \end{array} \right. \Leftrightarrow \left\{ \begin{array}{l} x > 0\\ x > - \frac{1}{2}\\ x > 1 \end{array} \right. \Leftrightarrow x > 1\)