Khối lượng của 1 mol proton theo đơn vị gam là
(biết hằng số Avogadro bằng 6,022×1023)
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Lời giải:
Báo saiĐáp án đúng là: A
1 mol proton có số hạt là: \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaaeaaaaaaaaa8 % qacaaIXaGaey41aqRaaGOnaiaacYcacaaIWaGaaGOmaiaaikdacqGH % xdaTcaaIXaGaaGima8aadaahaaWcbeqaa8qacaaIYaGaaG4maaaaaa % a!41D8! 1 \times 6,022 \times {10^{23}}\) (hạt)
1 hạt proton có khối lượng là \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaaeaaaaaaaaa8 % qacaaIXaGaaiilaiaaiAdacaaI3aGaaG4maiabgEna0kaaigdacaaI % WaWdamaaCaaaleqabaWdbiabgkHiTiaaikdacaaI0aaaaaaa!3FFB! 1,673 \times {10^{ - 24}}\) (g)
1 mol proton có khối lượng là \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaaeaaaaaaaaa8 % qacaaI2aGaaiilaiaaicdacaaIYaGaaGOmaiabgEna0kaaigdacaaI % WaWdamaaCaaaleqabaWdbiaaikdacaaIZaaaaOGaey41aqRaaGymai % aacYcacaaI2aGaaG4naiaaiodacqGHxdaTcaaIXaGaaGima8aadaah % aaWcbeqaa8qacqGHsislcaaIYaGaaGinaaaaaaa!4B0F! 6,022 \times {10^{23}} \times 1,673 \times {10^{ - 24}}\) (g)