Cho các chất sau:
\(\begin{array}{*{20}{l}} {}\\ {\left( 1 \right){\rm{ }}Cl{H_3}NC{H_2}COOH;}\\ {\left( 2 \right){\rm{ }}{H_2}NCH\left( {C{H_3}} \right) - CONH - C{H_2}COOH;}\\ {\left( 3 \right){\rm{ }}C{H_3} - N{H_3}N{O_3};}\\ {\left( 4 \right){\rm{ }}{{\left( {HOOCC{H_2}N{H_3}} \right)}_2}S{O_4};}\\ {\left( 5 \right){\rm{ }}Cl{H_3}NC{H_2} - CONH - C{H_2} - COOH;}\\ {\left( 6 \right){\rm{ }}C{H_3}COO{C_6}{H_5}.} \end{array}\)
Số chất trong dãy khi tác dụng với dung dịch NaOH (dư, đun nóng) thu được dung dịch chứa hai muối là bao nhiêu?
Hãy suy nghĩ và trả lời câu hỏi trước khi xem đáp án
Lời giải:
Báo sai\(\begin{array}{*{20}{l}} {\left( 1 \right){\rm{ }}Cl{H_3}NC{H_2}COOH{\rm{ }} + {\rm{ }}2NaOH{\rm{ }} \to {\rm{ }}{H_2}NC{H_2}COONa{\rm{ }} + {\rm{ }}NaCl{\rm{ }} + {\rm{ }}{H_2}O}\\ { \to {\rm{ }}2{\rm{ }}muoi:{\rm{ }}{H_2}NC{H_2}COONa,{\rm{ }}NaCl}\\ {\left( 2 \right){\rm{ }}{H_2}NCH\left( {C{H_3}} \right) - CONH - C{H_2}COOH{\rm{ }} + {\rm{ }}2NaOH{\rm{ }} \to {\rm{ }}{H_2}NCH\left( {C{H_3}} \right) - COONa{\rm{ }} + {\rm{ }}{H_2}N - C{H_2}COONa{\rm{ }} + {\rm{ }}{H_2}O}\\ { \to {\rm{ }}2{\rm{ }}muoi:{\rm{ }}{H_2}NCH\left( {C{H_3}} \right) - COONa,{\rm{ }}{H_2}N - C{H_2}COONa}\\ {\;\left( 3 \right){\rm{ }}C{H_3} - N{H_3}N{O_3}\; + {\rm{ }}NaOH{\rm{ }} \to {\rm{ }}NaN{O_3}\; + {\rm{ }}C{H_3} - N{H_2}\; + {\rm{ }}{H_2}O}\\ { \to {\rm{ }}1{\rm{ }}muoi:{\rm{ }}NaN{O_3}}\\ {\left( 4 \right){\rm{ }}{{\left( {HOOCC{H_2}N{H_3}} \right)}_2}S{O_4}\; + {\rm{ }}4NaOH{\rm{ }} \to {\rm{ }}2{H_2}N - C{H_2} - COONa{\rm{ }} + {\rm{ }}N{a_2}S{O_4}\; + {\rm{ }}4{H_2}O}\\ { \to {\rm{ }}2{\rm{ }}muoi:{\rm{ }}{H_2}N - C{H_2} - COONa,{\rm{ }}N{a_2}S{O_4}}\\ {\left( 5 \right){\rm{ }}Cl{H_3}N - C{H_2} - CONH - C{H_2} - COOH{\rm{ }} + {\rm{ }}3NaOH{\rm{ }} \to {\rm{ }}2{H_2}N - C{H_2} - COONa{\rm{ }} + {\rm{ }}NaCl{\rm{ }} + {\rm{ }}2{H_2}O}\\ { \to {\rm{ }}2{\rm{ }}muoi:{\rm{ }}{H_2}N - C{H_2} - COONa,{\rm{ }}NaCl}\\ {\left( 6 \right){\rm{ }}C{H_3}COO{C_6}{H_5}\; + {\rm{ }}2NaOH{\rm{ }} \to {\rm{ }}C{H_3}COONa{\rm{ }} + {\rm{ }}{C_6}{H_5}ONa{\rm{ }} + {\rm{ }}{H_2}O}\\ { \to {\rm{ }}2{\rm{ }}muoi:{\rm{ }}C{H_3}COONa,{\rm{ }}{C_6}{H_5}ONa} \end{array}\)
Vậy có 5 chất tác dụng với NaOH dư sinh ra 2 muối.
