Hàm số \(y = \frac{{ - 2{x^2} + 3x}}{{1 - x}}\) có đạo hàm cấp \(2\) bằng :

\[4y - y' = 0\]

\[4y + y'' = 0\]

\(y = y'tan2x\)

\({y^2} = {\left( {y'} \right)^2} = 4\)

Chỉ \[\left( I \right)\] đúng

Chỉ \[\left( {II} \right)\] đúng

Cả hai đều đúng

Cả hai đều sai

\[0\]

\[ - 1\]

\( - 2\)

\(5\)

\[{y^{\left( {10} \right)}}\left( 1 \right) = 0\]

\[{y^{\left( {10} \right)}}\left( 1 \right) = 10a + b\]

\[{y^{\left( {10} \right)}}\left( 1 \right) = 5a\]

\[{y^{\left( {10} \right)}}\left( 1 \right) = 10a\]

4 và 16

5 và 17

6 và 18

7 và 19

\({y^{(n)}} = \frac{{{{(1)}^{n - 1}}.3.n!}}{{{{(x + 2)}^{n + 1}}}}\)

\({y^{(n)}} = \frac{{{{( - 1)}^{n - 1}}.n!}}{{{{(x + 2)}^{n + 1}}}}\)

\({y^{(n)}} = \frac{{{{( - 1)}^{n - 1}}.3.n!}}{{{{(x - 2)}^{n + 1}}}}\)

\({y^{(n)}} = \frac{{{{( - 1)}^{n - 1}}.3.n!}}{{{{(x + 2)}^{n + 1}}}}\)

\({y^{(n)}} = \frac{{{{(2)}^n}.7.n!}}{{{{(x - 2)}^{n + 1}}}} - \frac{{{{(1)}^n}.5.n!}}{{{{(x - 3)}^{n + 1}}}}\)

\({y^{(n)}} = \frac{{{{( - 1)}^{n + 1}}.7.n!}}{{{{(x - 2)}^{n + 1}}}} - \frac{{{{( - 1)}^{n + 1}}.5.n!}}{{{{(x - 3)}^{n + 1}}}}\)

\({y^{(n)}} = \frac{{{{( - 1)}^n}.7.n!}}{{{{(x - 2)}^n}}} - \frac{{{{( - 1)}^n}.5.n!}}{{{{(x - 3)}^n}}}\)

\({y^{(n)}} = \frac{{{{( - 1)}^n}.7.n!}}{{{{(x - 2)}^{n + 1}}}} - \frac{{{{( - 1)}^n}.5.n!}}{{{{(x - 3)}^{n + 1}}}}\)

\({y^{(n)}} = \frac{{{{( - 1)}^{n + 1}}.3.5...(3n - 1)}}{{\sqrt {{{(2x + 1)}^{2n - 1}}} }}\)

\({y^{(n)}} = \frac{{{{( - 1)}^{n - 1}}.3.5...(2n - 1)}}{{\sqrt {{{(2x + 1)}^{2n - 1}}} }}\)

\({y^{(n)}} = \frac{{{{( - 1)}^{n + 1}}.3.5...(2n - 1)}}{{\sqrt {{{(2x + 1)}^{2n + 1}}} }}\)

\({y^{(n)}} = \frac{{{{( - 1)}^{n + 1}}.3.5...(2n - 1)}}{{\sqrt {{{(2x + 1)}^{2n - 1}}} }}\)

\({y^{(n)}} = \frac{{5.{{( - 1)}^n}.n!}}{{{{(x - 2)}^{n + 1}}}} + \frac{{3.{{( - 1)}^n}.n!}}{{{{(x - 1)}^{n + 1}}}}\)

\({y^{(n)}} = \frac{{5.{{( - 1)}^n}.n!}}{{{{(x + 2)}^{n + 1}}}} - \frac{{3.{{( - 1)}^n}.n!}}{{{{(x - 1)}^{n + 1}}}}\)

\({y^{(n)}} = \frac{{5.{{( - 1)}^n}.n!}}{{{{(x - 2)}^{n + 1}}}}:\frac{{3.{{( - 1)}^n}.n!}}{{{{(x - 1)}^{n + 1}}}}\)

\({y^{(n)}} = \frac{{5.{{( - 1)}^n}.n!}}{{{{(x - 2)}^{n + 1}}}} - \frac{{3.{{( - 1)}^n}.n!}}{{{{(x - 1)}^{n + 1}}}}\)

\[{y^{(n)}} = \frac{{{{( - 1)}^n}.3.n!}}{{{{(x + 3)}^{n + 1}}}} + \frac{{{{( - 1)}^n}.2.n!}}{{{{(x + 2)}^{n + 1}}}}\]

\[{y^{(n)}} = \frac{{{{( - 1)}^n}.3.n!}}{{{{(x + 3)}^n}}} - \frac{{{{( - 1)}^n}.2.n!}}{{{{(x + 2)}^n}}}\]

\[{y^{(n)}} = \frac{{{{( - 1)}^n}.3.n!}}{{{{(x + 3)}^{n - 1}}}} - \frac{{{{( - 1)}^n}.2.n!}}{{{{(x + 2)}^{n - 1}}}}\]

\[{y^{(n)}} = \frac{{{{( - 1)}^n}.3.n!}}{{{{(x + 3)}^{n + 1}}}} - \frac{{{{( - 1)}^n}.2.n!}}{{{{(x + 2)}^{n + 1}}}}\]