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Cho Z = 2X - Y + 5, biết:

(X, Y)

(1, -1)

(1, 0)

(1, 1)

(2, -1)

(2, 0)

(2, 1)

Pij

0,1

0,15

0,05

0,3

0,2

0,2

Tính P[Z = 8].

A.

P[Z = 8] = 0,2

B.
P[Z = 8] = 0,4
C.
P[Z = 8] = 0,5
D.
P[Z = 8] = 0,3
Trả lời:

Đáp án đúng: B


We want to find P[Z = 8], where Z = 2X - Y + 5. This means we want to find cases where 2X - Y + 5 = 8, or 2X - Y = 3. We examine all possible (X, Y) pairs and their probabilities. * (1, -1): 2(1) - (-1) = 3. Z = 8, P(1, -1) = 0.1 * (1, 0): 2(1) - 0 = 2 * (1, 1): 2(1) - 1 = 1 * (2, -1): 2(2) - (-1) = 5 * (2, 0): 2(2) - 0 = 4 * (2, 1): 2(2) - 1 = 3. Z = 8, P(2, 1) = 0.2 Thus, P[Z = 8] = P(1, -1) + P(2, 1) = 0.1 + 0.2 = 0.3

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