Cho Z = 2X - Y + 5, biết:
|
(X, Y) |
(1, -1) |
(1, 0) |
(1, 1) |
(2, -1) |
(2, 0) |
(2, 1) |
|
Pij |
0,1 |
0,15 |
0,05 |
0,3 |
0,2 |
0,2 |
Tính P[Z = 8].
Trả lời:
Đáp án đúng: B
We want to find P[Z = 8], where Z = 2X - Y + 5. This means we want to find cases where 2X - Y + 5 = 8, or 2X - Y = 3. We examine all possible (X, Y) pairs and their probabilities.
* (1, -1): 2(1) - (-1) = 3. Z = 8, P(1, -1) = 0.1
* (1, 0): 2(1) - 0 = 2
* (1, 1): 2(1) - 1 = 1
* (2, -1): 2(2) - (-1) = 5
* (2, 0): 2(2) - 0 = 4
* (2, 1): 2(2) - 1 = 3. Z = 8, P(2, 1) = 0.2
Thus, P[Z = 8] = P(1, -1) + P(2, 1) = 0.1 + 0.2 = 0.3





