Một khối khí được làm nóng bằng cách truyền 40 kJ cho nó. Đồng thời, nó được nén bởi lực thực hiện được công 30 kJ. Độ tăng nội năng của khối khí đó là bao nhiêu kJ?
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Định luật 1 của nhiệt động lực học ΔU = A + Q.
Vì khối khí nhận nhiệt nên Q = 40 kJ, được nén bởi lực thực hiện công nên A = 30 kJ.
Độ tăng nội năng của khối khí đó là
ΔU = 30 + 40 = 70 kJ.
Bộ Đề Kiểm Tra Tham Khảo Giữa Học Kì I - Môn Vật lí 12 - Kết Nối Tri Thức được biên soạn và tổng hợp những kiến thức cơ bản đã học nhằm giúp học sinh củng cố kiến thức, đánh giá năng lực, và chuẩn bị tốt hơn cho các kỳ thi quan trọng sắp tới.
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