Cho đoạn chương trìnhsau: n = input('Nhap gia tri n:'); /B = 0; C = 1;14 /for k = 1:n /B = B+(2*k+1); /C = C*k; /end /A=B/C Đoạn chương trìnhthực hiện tính biểu thức:
Trả lời:
Đáp án đúng: B
The code calculates A = (sum from k=1 to n of (2*k + 1)) / n!
* n = input('Nhap gia tri n:') - Reads the value of n from the user.
* B = 0; C = 1 - Initializes B to 0 and C to 1.
* for k = 1:n - Loops from k = 1 to n.
* B = B + (2*k + 1) - Adds (2*k + 1) to B in each iteration. This computes the sum of (2*1 + 1) + (2*2 + 1) + ... + (2*n + 1), which is the sum from k=1 to n of (2*k + 1).
* C = C * k - Multiplies C by k in each iteration. This computes the product 1 * 2 * ... * n, which is n!.
* end - Ends the loop.
* A = B/C - Calculates A = B/C. Therefore, A = (sum from k=1 to n of (2*k + 1)) / n!





