Câu hỏi:

Yến ơi bố cháu có nhà không?

\(2x + 1 = 3\)

Đề trắc nghiệm môn Toán năm nay dễ quá!

\(1 + 1 = 3\)

\(M = \left[ {2;\,5} \right]\)

\(M = \left( {2;\,5} \right)\)

\(M = (2;\,5{\rm{]}}\)

\(M = \left[ {2;\,5} \right)\)

\(1 \le m \le 2\)

\(m = 2\)

\(1 < m < 2\)

\(m = 1\)

\(\left( {x;\,y} \right) = \left( {0;\, - 2} \right)\)

\(\left( {x;\,y} \right) = \left( {1;\, - 1} \right)\)

\(\left( {x;\,y} \right) = \left( {0;\,0} \right)\)

\(\left( {x;\,y} \right) = \left( { - 1;\,1} \right)\)

\(\left\{ \begin{array}{l}2x + 3{y^2} > 5\\ - 3x - 5y \le - 6\end{array} \right.\)

\(\left\{ \begin{array}{l}3{x^3} - 5y \ge 8\\ - x - 4y \le 20\end{array} \right.\)

\(\left\{ \begin{array}{l} - 3x + y \le - 1\\4x - 7y > 5\end{array} \right.\)

\(\left\{ \begin{array}{l}3x + y \le 9\\\frac{2}{x} - 3y > 1\end{array} \right.\)

\(\overrightarrow {AB} - \overrightarrow {BC} = \overrightarrow {BD} \)

\(\overrightarrow {AB} - \overrightarrow {BC} = \overrightarrow {AC} \)

\(\overrightarrow {AB} - \overrightarrow {BC} = \overrightarrow {CA} \)

\(\overrightarrow {AB} - \overrightarrow {BC} = \overrightarrow {DB} \)

\(\frac{a}{{{\rm{sin}}A}} = 2R\)

\(\frac{a}{{{\rm{sin}}A}} = \frac{c}{{{\rm{sin}}C}}\)

\(b = 2R.{\rm{sin}}B\)

\(b{\rm{sin}}B = 2R\)

\(\left\{ { - 3} \right\}\)

\(\left[ { - 3;10} \right]\)

\(\emptyset \)

\(( - \infty ;10{\rm{]}}\)

\(\left( {1;\,2} \right)\)

\(\left( {3;\, - 1} \right)\)

\(\left( {1;\, - 2} \right)\)

\(\left( {3;\,1} \right)\)

\(P = \frac{4}{3}\)

\(P = \frac{3}{4}\)

\(P = - \frac{3}{4}\)

\(P = - \frac{4}{3}\)