Câu hỏi:

3

1

9

-1

120

150

1200

1500

\(2{{\rm{a}}^3}\)

\(2{{\rm{a}}^3} + 2{{\rm{b}}^3}\)

\(2{{\rm{a}}^2} - 6{{\rm{a}}^2}{\rm{b}}\)

\({\rm{\;}}2{{\rm{a}}^3} + 6{\rm{a}}{{\rm{b}}^2}\)

Hai cạnh bên bằng nhau

Hai đường chéo bằng nhau

Hai góc đối bằng nhau

Hai cạnh đối bằng nhau

MN = PQ

MP = NQ

NP = MQ

MN = MQ

\( - 36\)

\( - 36{a^2}{b^2}\)

\(36{a^2}{b^2}\)

\( - 36{a^2}\)

\(\frac{{176}}{{27}}\)

\(\frac{{27}}{{176}}\)

\(\frac{{17}}{{27}}\)

\(\frac{{116}}{{27}}\)

\({\left( {x + y} \right)^2} = \left( {x + y} \right)\left( {x + y} \right)\)

\({x^2} - {y^2} = \left( {x + y} \right)\left( {x - y} \right)\)

\({\left( { - x - y} \right)^2} = {\left( { - x} \right)^2} - 2\left( { - x} \right)y + {y^2}\)

\(\left( {x + y} \right)\left( {x + y} \right) = {y^2} - {x^2}\)

0

1

2

3

\(8 + 12y + 6{y^2} + {y^3} = \left( {8 + {y^3}} \right)\)

\({a^3} + 3{a^2} + 3a + 1 = {\left( {a + 1} \right)^3}\)

\({\left( {2x - y} \right)^3} = 2{x^3} - 6{x^2}y + 6xy - {y^3}\)

\({\left( {3a + 1} \right)^3} = 3{a^3} + 9{a^2} + 3a + 1\)