What is output of following code? void main() { int i = 400; int *ptr = &i *++ptr = 2; printf("%d %d", i, *ptr); getch(); }

What will be output of following program? #include #include void main() { int i = 5; int *p; p = &i printf(" %u %u", *&p , &*p); getch(); }

What is output? #include #include int main() { int array[2][2][3]={0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11}; printf("%d", array[1][0][2]); getch(); }

What is output? (assuming that the array begins at the location 1002 and size of an integer is 4 bytes) #include #include int main() { int a[3][4] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 }; printf("%u, %u, %u\n", a[0]+1, *(a[0]+1), *(*(a+0)+1)); getch(); }

What is output? #include #include void main() { struct site { char name[] = "laptrinhc++"; int year = 2; }; struct site *ptr; printf("%s ", ptr->name); printf("%d", ptr->year); getch(); }

C++ programming language was designed and developed by ___ at ___.

%= is not a operator in C++

Preprocessor #define macro and inline functions use the same mechanism.

The new operator returns the address and size of the memory block that it allocates.

What is output of code? #include #include void main() { int a = 80; if(a++ > 80) printf("C/C++ %d", a); else printf("Java %d", a); getch(); }

Đầu ra là gì? #include int main() { int x = 5, y = 10, z = 15; printf("%d %d %d"); return 0; }