Chọn phát biểu sai: Một host được ghi nhận địa chỉ IP là 190.162.4.190/255.255.255.248:

The subnet mask /255.255.255.248 corresponds to /29. This means that 29 bits are used for the network ID, and the remaining 3 bits are for the host ID. Option 1: Number of hosts in each network is 6. With 3 host ID bits, the maximum number of hosts is 2^3 = 8. Subtracting the network address and the broadcast address, the number of usable hosts is 8 - 2 = 6. This statement is correct. Option 2: Number of subnets is 8190. Class C address, by default has 24 network bits. With a /29 subnet mask, we borrow 29 - 24 = 5 bits from the host part for the network part. Therefore, the number of subnets is 2^5 = 32 networks. This statement is incorrect because the number of subnets should be 32, not 8190. Option 3: Borrow 5 bits. As explained above, we borrow 5 bits. The question says 13 bits, which is incorrect. Option 4: Addresses in the same network as this IP are: 190.162.4.185 to 190.162.4.190. With a /29 subnet (255.255.255.248), the step is 8 (256-248). The network address is 190.162.4.184 (190.162.4.190 AND 255.255.255.248 = 190.162.4.184). So, the address range is from 190.162.4.184 to 190.162.4.191. The usable host addresses are 190.162.4.185 to 190.162.4.190. This statement is correct. The incorrect statements are 2 and 3, but the question only asks to choose 1 answer, so choose the most clearly wrong answer.