Hòa tan hết 2,43 gam Al trong dung dịch NaOH, thu được V ml khí H2 (đktc). Giá trị của V là
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Lời giải:
Báo sai\(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeaacaGaaiaabeqaamaabaabaaGceaqabeaacaaIXa % GaamyqaiaadYgacqGHRaWkcaaIYaGaamisamaaBaaaleaacaaIYaaa % beaakiaad+eacqGHRaWkcaaIYaGaamOtaiaadggacaWGpbGaamisai % abgkziUkaaikdacaWGobGaamyyaiaadgeacaWGSbGaam4tamaaBaaa % leaacaaIYaaabeaakiabgUcaRiaaiodacaWGibWaaSbaaSqaaiaaik % daaeqaaaGcbaGaaGimaiaacYcacaaIWaGaaGyoaiaac6cacaGGUaGa % aiOlaiaac6cacaGGUaGaaiOlaiaac6cacaGGUaGaaiOlaiaac6caca % GGUaGaaiOlaiaac6cacaGGUaGaaiOlaiaac6cacaGGUaGaaiOlaiaa % c6cacaGGUaGaaiOlaiaac6cacaGGUaGaaiOlaiaac6cacaGGUaGaai % Olaiaac6cacaGGUaGaaiOlaiaac6cacaGGUaGaaiOlaiaac6cacaGG % UaGaaiOlaiaac6cacaGGUaGaaiOlaiaac6cacaGGUaGaaiOlaiaac6 % cacaGGUaGaaiOlaiaac6cacaGGUaGaaiOlaiaac6cacaGGUaGaaiOl % aiaaicdacaGGSaGaaGymaiaaiodacaaI1aaaaaa!76CD! \begin{gathered} 1Al + 2{H_2}O + 2NaOH \to 2NaAl{O_2} + 3{H_2} \hfill \\ 0,09...................................................0,135 \hfill \\ \end{gathered}\)
\(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeaacaGaaiaabeqaamaabaabaaGcbaGaeyOKH4Qaam % OvamaaBaaaleaacaWGibWaaSbaaWqaaiaaikdaaeqaaaWcbeaakiab % g2da9iaaicdacaGGSaGaaGymaiaaiodacaaI1aGaaiOlaiaaikdaca % aIYaGaaiilaiaaisdacqGH9aqpcaaIZaGaaiilaiaaicdacaaIYaGa % aGinaaaa!4795! \to {V_{{H_2}}} = 0,135.22,4 = 3,024\) lít = 3024 ml