Cho hàm số \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamiAamaabm % aabaGaamiEaaGaayjkaiaawMcaaiabg2da9maabmaabaGaaGymaiaa % iwdacqGHsislcaaIXaGaaGOmaiaadIhaaiaawIcacaGLPaaadaahaa % WcbeqaaiaaiIdaaaaaaa!41C0! h\left( x \right) = {\left( {15 - 12x} \right)^8}\). Tìm \(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaa8qaaeaaca % WGObWaaeWaaeaacaWG4baacaGLOaGaayzkaaGaaeizaiaadIhaaSqa % beqaniabgUIiYdaaaa!3D46! \int {h\left( x \right){\rm{d}}x} \)

\(% MathType!MTEF!2!1!+- % feaahqart1ev3aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGceaqabeaadaWdba % qaamaabmaabaGaaGymaiaaiwdacqGHsislcaaIXaGaaGOmaiaadIha % aiaawIcacaGLPaaadaahaaWcbeqaaiaaiIdaaaGccaqGKbGaamiEaa % Wcbeqab0Gaey4kIipakiabg2da9iabgkHiTmaalaaabaGaaGymaaqa % aiaaigdacaaIYaaaamaapeaabaWaaeWaaeaacaaIXaGaaGynaiabgk % HiTiaaigdacaaIYaGaamiEaaGaayjkaiaawMcaamaaCaaaleqabaGa % aGioaaaakiaabsgadaqadaqaaiaaigdacaaI1aGaeyOeI0IaaGymai % aaikdacaWG4baacaGLOaGaayzkaaaaleqabeqdcqGHRiI8aOGaeyyp % a0JaeyOeI0YaaSaaaeaacaaIXaaabaGaaGymaiaaikdaaaGaaiOlam % aalaaabaGaaGymaaqaaiaaiMdaaaWaaeWaaeaacaaIXaGaaGynaiab % gkHiTiaaigdacaaIYaGaamiEaaGaayjkaiaawMcaamaaCaaaleqaba % GaaGyoaaaakiabgUcaRiaadoeaaeaacqGH9aqpcqGHsisldaWcaaqa % aiaaigdaaeaacaaIXaGaaGimaiaaiIdaaaWaaeWaaeaacaaIXaGaaG % ynaiabgkHiTiaaigdacaaIYaGaamiEaaGaayjkaiaawMcaamaaCaaa % leqabaGaaGyoaaaakiabgUcaRiaadoeaaaaa!739D! \begin{array}{l} \int {{{\left( {15 - 12x} \right)}^8}{\rm{d}}x} = - \frac{1}{{12}}\int {{{\left( {15 - 12x} \right)}^8}{\rm{d}}\left( {15 - 12x} \right)} = - \frac{1}{{12}}.\frac{1}{9}{\left( {15 - 12x} \right)^9} + C\\ = - \frac{1}{{108}}{\left( {15 - 12x} \right)^9} + C \end{array}\)