Tìm x biết \(\frac{{11}}{3}:\left( {\frac{1}{2}x - \frac{5}{3}} \right) + 1 = \frac{1}{9}\)
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Lời giải:
Báo sai
\(\begin{array}{l}
\frac{{11}}{3}:\left( {\frac{1}{2}x - \frac{5}{3}} \right) + 1 = \frac{1}{9}\\
\frac{{11}}{3}:\left( {\frac{1}{2}x - \frac{5}{3}} \right) = \frac{1}{9} - 1\\
\frac{{11}}{3}:\left( {\frac{1}{2}x - \frac{5}{3}} \right) = \frac{{ - 8}}{9}\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{1}{2}x - \frac{5}{3} = \frac{{11}}{3}:\frac{{ - 8}}{9}\\
\,\,\,\,\,\,\,\,\,\,\,\frac{1}{2}x - \frac{5}{3} = \frac{{11}}{3}.\frac{9}{{ - 8}}\\
\,\,\,\,\,\,\,\,\,\,\,\frac{1}{2}x - \frac{5}{3} = \frac{{ - 33}}{8}\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{1}{2}x = \frac{{ - 33}}{8} + \frac{5}{3}\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{1}{2}x = \frac{{ - 59}}{{24}}\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = \frac{{ - 59}}{{24}}:\frac{1}{2}\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = \frac{{ - 59}}{{24}}.2 = \frac{{ - 59}}{{12}}
\end{array}\)
