Tìm x biết \(\begin{array}{l} 3\frac{1}{4} - 47.x + \frac{5}{6} = \frac{2}{5} + \frac{4}{3} \end{array}\)
Hãy suy nghĩ và trả lời câu hỏi trước khi xem đáp án
Lời giải:
Báo sai\(\begin{array}{l} 3\frac{1}{4} - 47.x + \frac{5}{6} = \frac{2}{5} + \frac{4}{3}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,47.x = 3\frac{1}{4} + \frac{5}{6} - \frac{2}{5} - \frac{4}{3}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,47.x = \frac{{13}}{4} + \frac{5}{6} - \frac{2}{5} - \frac{4}{3}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,47.x = \frac{{195}}{{60}} + \frac{{50}}{{60}} - \frac{{24}}{{60}} - \frac{{80}}{{60}}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,47.x = \frac{{141}}{{60}}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,47.x = \frac{{47}}{{20}}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = \frac{{47}}{{20}}:47 = \frac{1}{{20}} \end{array}\)