Tìm x biết \(\begin{array}{l} 2\frac{2}{3} - 3x + \frac{1}{6} = \frac{4}{3} - \left( {\frac{{ - 5}}{6}} \right) \end{array}\)
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Lời giải:
Báo sai\(\begin{array}{l} 2\frac{2}{3} - 3x + \frac{1}{6} = \frac{4}{3} - \left( {\frac{{ - 5}}{6}} \right)\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{3x}} = 2\frac{2}{3} + \frac{1}{6} - \frac{4}{3} - \frac{5}{6}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{3x}} = \frac{8}{3} + \frac{1}{6} - \frac{4}{3} - \frac{5}{6}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{3x}} = \left( {\frac{8}{3} - \frac{4}{3}} \right) + \left( {\frac{1}{6} - \frac{5}{6}} \right)\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{3x}} = \frac{4}{3} - \frac{4}{6}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{3x}} = \frac{2}{3}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{x}} = \frac{2}{9} \end{array}\)
